1. If the sodium concentration in blood plasma is 0.140 M, and Ksp for sodium urate is 5.76Ã10â8, what minimum concentration of urate would result in the precipitation of odium urate?

2. Use the appropriate values of Ksp and Kf to find the equilibrium constant for the following reaction:

FeS(s)+6CNâ(aq)âFe(CN)4â6(aq)+S2â(aq)

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126. Gout-a condition that results in joint swelling and pain-is caused by the formation of sodium urate (NaCsH3N403) crystals within tendons, cartilage, and ligaments. Sodium urate precipi- tates out of blood plasma when uric acid levels become abnor- mally high. This sometimes happens as a result of eating too many rich foods and consuming too much alcohol, which is why gout is sometimes referred to as the "disease of kings.” If the sodium concentration in blood plasma is 0.140 M, and Ksp for sodium urate is 5.76 x 108, what minimum concentration of urate would result in precipitation?

111. Use the appropriate values of Ksp and Ki to find the equilibrium constant for the reaction. Fes(s) + 6 CN-(aq) Fe(CN)64-(aq) + 52- (aq)

1. A beaker with 2.00Ã102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and conjugate base in this buffer is 0.100 M. A student adds 7.90 mL of a 0.490 M HCl solution to the beaker. How much will the pH change? The pKa of acetic acid is 4.740. find ÎpH =

2. When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, Kf.

For example, the iron(II) ion, Fe2+, can combine with the cyanide ion, CNâ, to form the complex [Fe(CN)6]4â according to the equation

Fe2+(aq)+6CNâ(aq)â[Fe(CN)6]4â(aq)

where Kf=4.21Ã1045.

The average human body contains 5.20 L of blood with a Fe2+ concentration of 2.70Ã10^â5M . If a person ingests 5.00 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? find % Fe2+

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