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23 Nov 2019

2. Use symmetry to consider the bonding in thebenzenemolecule, C6H6. You needn't gettoocarried away with it. You can assume, for instance, that asigmabonding network will hold the planar molecule together. Focusyourattention instead on the pi bonding that exists between the6carbon atoms. A reasonable basis set would be the 6 porbitals,perpendicular to the moleculare plane, that mightparticipate insuch bonding.
Your answer should include: the number of moleculeorbitalsexpected for each of the irreducible representation ofthemolecule's point group; descriptions (equations and sketches)ofsymmetry orbitals that could be used to form thosemolecularorbitals; and your best estimate of the resulting energyleveldiagram.
Ok, the π bonding in benzene is written up in many,manyplaces. I hope you"ve been able to check your results. Nowtrythese additional questions:
What happens to the π molecularorbitals if a heteroatom isinserted into the ring, turning benzeneinto pyridine?
What happens if a second nitrogen replaces acarbon in thepara-position in pyridine?
What would removing one electron frombenzene do to theenergies of its π orbitals?
N.B. I have answered most part of the above questionexceptthat the ones mark in RED is not done yet. So, can you helpmeplease?

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