Question

Aluminum reacts with chlorine gas to form aluminum chloride via thefollowing reaction
2Al(s)+3Cl2(g) -> 2AlCl3(s)
You are given 14.0 g of aluminum and 19.0 g of chlorine gas.

1) If you had excess chlorine, how many moles of of aluminumchloride could be produced from 14.0 g of aluminum?

2)If you had excess aluminum, how many moles of aluminum chloridecould be produced from 19.0 g of chlorine gas, Cl2?