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Lead(II) ions can be removed from solution with KC1 according to the balanced chemical reaction below. Pb^2+(aq) + 2 KCl(aq) rightarrow PbCl_2(s) + 2 K^+(aq) When 28.5 g of KC1 is added to a solution containing 25.7 g Pb^2+, 29.4 g of PbCl_2 is formed. What is the percent yield for this reaction?
Lead(II) ions can be removed from solution with KC1 according to the balanced chemical reaction below. Pb^2+(aq) + 2 KCl(aq) rightarrow PbCl_2(s) + 2 K^+(aq) When 28.5 g of KC1 is added to a solution containing 25.7 g Pb^2+, 29.4 g of PbCl_2 is formed. What is the percent yield for this reaction?
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Jean KeelingLv2
13 Nov 2019
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