1
answer
0
watching
269
views
19 Nov 2019
Use the following to answer questions 6-7. For the reaction A rightarrow Products, successive half-lives arc observed to be 10.0 min and 40.0 min. The reaction follows the integrated rate law A) [A] = -kt + [A]_0 B) In [A] = -kt + In [A]_0 C) 1/[A] = kt + 1/[A]_0) D) 1/[A]^2 = kt + 1/[A]_0^2 E) none of these At the beginning of the reaction, [A] was 0.68 M. The numerical value of the rate constant is (using the units given) A) 0.069 B) 0.15 C) 10. D) 0.034 E) none of these
Use the following to answer questions 6-7. For the reaction A rightarrow Products, successive half-lives arc observed to be 10.0 min and 40.0 min. The reaction follows the integrated rate law A) [A] = -kt + [A]_0 B) In [A] = -kt + In [A]_0 C) 1/[A] = kt + 1/[A]_0) D) 1/[A]^2 = kt + 1/[A]_0^2 E) none of these At the beginning of the reaction, [A] was 0.68 M. The numerical value of the rate constant is (using the units given) A) 0.069 B) 0.15 C) 10. D) 0.034 E) none of these
Irving HeathcoteLv2
22 Jul 2019