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18 Nov 2019
A Comparison of Average Enthalpy (BE) and Heat of Formation:
Please answer both A and B of the following problem below:
For the reaction: 2C2H6(g) + 7O2(g) - 4CO2(g) + 6H2O(g)
A) Predict the enthalpy of reaction from the average bond energies
B) Calculate the enthalpy of reaction from the standard enthalpies of formation of the reactant and product molecules and compare the results with your answer for part A
Hint: for part (a) ïHo = total energy input â total energy released
Hint for part (b) ) ïHo = summation of products â summation of reactants
Heats of formation here: ïHo C2H6(g) = -84.7 kJ/mol, ïHo CO2 = -393.5 kJ/mol, ïHo H2O = -241.8 kJ/mol
A Comparison of Average Enthalpy (BE) and Heat of Formation:
Please answer both A and B of the following problem below:
For the reaction: 2C2H6(g) + 7O2(g) - 4CO2(g) + 6H2O(g)
A) Predict the enthalpy of reaction from the average bond energies
B) Calculate the enthalpy of reaction from the standard enthalpies of formation of the reactant and product molecules and compare the results with your answer for part A
Hint: for part (a) ïHo = total energy input â total energy released
Hint for part (b) ) ïHo = summation of products â summation of reactants
Heats of formation here: ïHo C2H6(g) = -84.7 kJ/mol, ïHo CO2 = -393.5 kJ/mol, ïHo H2O = -241.8 kJ/mol
Jean KeelingLv2
2 Apr 2019