Exercise 1: Determining the Concentration of Acetic Acid
Data Table 1. NaOH Titration Volume.
Initial NaOH Volume (mL)
Final NaOH Volume (mL)
Total volume of NaOH used (mL)
Trial 1
9
.5
8.5
Trial 2
9
.25
8.25
Trial 3
9
0
9
Average Volume of NaOH Used (mL) : 8.58
Data Table 2. Concentration of CH3COOH in Vinegar.
Average volume of NaOH used (mL)
Concentration CH3COOH in vinegar (mol/L)
% CH3COOH in vinegar
* I don't know if I am doing it correctly, and end up with crazy numbers. Can someone PLEASE break it down easily for me?
Question
The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percent error between your result and the manufacturerâs statement?
UPDATE: NaOH is 0.5M
I DO NOT know CH3COOH.... It was for me to find out in that chart.....
UPDATE AGAIN: I know he acedic acid was not given. That was suppose to be what I am figuring out. This is what it says for data:
UPDATE AGAIN: I DO NOT KNOW THE VOLUME BECAUSE THAT IS WHAT IS IN THE BLANKS THAT I NEED TO FIGURE OUT!!!!!!!!!!!
28. 28. Repeat Steps 15 through 27 two additional times (Trial 2 and Trial 3, using the vinegar provide in the lab kit. 29. Average results from trials in Data Table 1 and Data Table 2 of your the the three and record 2 of Lab Report Assistant. 30. Using the following equation, determine the average concentration (moles per liter) of acetic I acid (CH, COOH) present in your vinegarRecord the concentration in Data Table 2. M CH ,coOH at NaOH x mol No. 1 mol CH,cooH ..ca. 1 mol NaOH 31. Using the following equation, determine % concentration (mass percentof acetic acid (CH, COOH) in the vinegar and record it in Data Table 2. Note: The density of vinegar is .00 g/ml and the molecular mass of vinegar is 6005 g/mol Namcoon . molCH, COOH 11 A 1000 mt 1L vinegar 100 vinegar 1 mL vinegar , SOOECH.COON Imo CHCOOH Cleanup :
Exercise 1: Determining the Concentration of Acetic Acid
Data Table 1. NaOH Titration Volume.
Initial NaOH Volume (mL) | Final NaOH Volume (mL) | Total volume of NaOH used (mL) | |
Trial 1 | 9 | .5 | 8.5 |
Trial 2 | 9 | .25 | 8.25 |
Trial 3 | 9 | 0 | 9 |
Average Volume of NaOH Used (mL) : 8.58 |
Data Table 2. Concentration of CH3COOH in Vinegar.
Average volume of NaOH used (mL) | Concentration CH3COOH in vinegar (mol/L) | % CH3COOH in vinegar |
* I don't know if I am doing it correctly, and end up with crazy numbers. Can someone PLEASE break it down easily for me?
Question
The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percent error between your result and the manufacturerâs statement?
UPDATE: NaOH is 0.5M
I DO NOT know CH3COOH.... It was for me to find out in that chart.....
UPDATE AGAIN: I know he acedic acid was not given. That was suppose to be what I am figuring out. This is what it says for data:
UPDATE AGAIN: I DO NOT KNOW THE VOLUME BECAUSE THAT IS WHAT IS IN THE BLANKS THAT I NEED TO FIGURE OUT!!!!!!!!!!!