The answer is D but I don't know why. Please provide an explanation to your answer.
Predict the products obtained from electrolysis of a 1 M AlBr_3 solution. Note that 2H_2O(l) + 2e^- rightarrow H_2(g) + 2OH^-(aq), E degree_red = -0.83 V, and O_2(g) + 4H^+(aq) + 4e^- rightarrow 2H_2O(l), E degree_red = +1.23 V Al and Br_2 Al and O_2 H_2 and O_2 H_2 and Br_2 Al and H_2
? Given are the reduction potential of the different species in an aqueous 
value
