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17 Nov 2019
For questions consider the chemical reaction for the formation of ammonia: N_2(g) + 3H_2(g) 2NH_3(g) Delta G degree = -34 kJ What is the equilibrium constant (K) for the formation of ammonia at 298 K? 9.1 times 10^5 7.7 times 10^3 1.3 times 10^-3 1.7 times 10^-6 If you start with 0.60 atm N_2(g), 0.44 atm H_2(g), and 0.10 atm NH_3 (g) at 298K, then the reaction proceeds to the because right Delta G_SYS = -38 kJ left Delta G_SYS = -38 kJ right Delta G_SYS = +38 kJ left Delta G_SYS = +38 kJ left Delta G_SYS = 0 kJ
For questions consider the chemical reaction for the formation of ammonia: N_2(g) + 3H_2(g) 2NH_3(g) Delta G degree = -34 kJ What is the equilibrium constant (K) for the formation of ammonia at 298 K? 9.1 times 10^5 7.7 times 10^3 1.3 times 10^-3 1.7 times 10^-6 If you start with 0.60 atm N_2(g), 0.44 atm H_2(g), and 0.10 atm NH_3 (g) at 298K, then the reaction proceeds to the because right Delta G_SYS = -38 kJ left Delta G_SYS = -38 kJ right Delta G_SYS = +38 kJ left Delta G_SYS = +38 kJ left Delta G_SYS = 0 kJ
Sixta KovacekLv2
13 May 2019