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16 Nov 2019

A Standard Hydrogen Electrode (SHE) is used as the anode for an electrochemical cell and magnesium metal and 1 M magnesium ion solution is used for the cathode of an electrochemical cell. What is the potential of this cell?

Hg2+ (aq) + 2e- → Hg(l) E° = 0.854 V

Na+ (aq) + e-→ Na(s) E° = -2.71 V

Mg2+ (aq) + 2e- → Mg(s) E° = -2.37 V

Ni2+ (aq) + 2e- → Ni(s) E° = -0.28 V

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Sixta Kovacek
Sixta KovacekLv2
15 Apr 2019

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Related questions

Calculate the standard cell potential for each of the following electrochemical cells.

Standard Electrode Potentials at 25 ∘C
Reduction half-reaction E∘(V)
Ag+(aq)+e− →Ag(s) 0.80
Sn2+(aq)+2e− →Sn(s) -0.14
ClO2(g)+e− →ClO2−(aq) 0.95
I2(s)+2e− →2I−(aq) 0.54
Ni2+(s)+2e− →Ni(s) -0.23
O2(g)+4H+(aq)+2e− →2H2O(l)

1.23

1. 2Ag+(aq)+Sn(s)→2Ag(s)+Sn2+(aq)

2. 2ClO2(g)+2I−(aq)→2ClO−2(aq)+I2(s)

3. O2(g)+4H+(aq)+2Ni(s)→2H2O(l)+2Ni2+(aq)

Constants

The following values may be useful when solving this tutorial.

Constant Value
E∘Cu 0.337 V
E∘Ni -0.257 V
R 8.314 J⋠mol−1⋠K−1
F 96,485 C/mol
T 298 K

Part A

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. The two half-reactions that occur in the cell are

Cu2+(aq)+2e−→Cu(s) and Ni(s)→Ni2+(aq)+2e−

The net reaction is

Cu2+(aq)+Ni(s)→Cu(s)+Ni2+(aq)

Use the given standard reduction potentials in your calculation as appropriate.

Reduction half-reaction E∘ (V)
Ag+(aq)+e−→Ag(s) 0.80
Cu2+(aq)+2e−→Cu(s) 0.34
Sn4+(aq)+4e−→Sn(s) 0.15
2H+(aq)+2e−→H2(g) 0
Ni2+(aq)+2e−→Ni(s) −0.26
Fe2+(aq)+2e−→Fe(s) −0.45
Zn2+(aq)+2e−→Zn(s) −0.76
Al3+(aq)+3e−→Al(s) −1.66
Mg2+(aq)+2e−→Mg(s) −2.37

1)

Use the table of standard reduction potentials given above to calculate the equilibrium constant at standard temperature (25 ∘C) for the following reaction: Fe(s)+Ni2+(aq)→Fe2+(aq)+Ni(s)

2)

Calculate the standard cell potential (E∘) for the reaction

X(s)+Y+(aq)→X+(aq)+Y(s)

if K = 3.80×10−4.

Express your answer to three significant figures and include the appropriate units.

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