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16 Nov 2019

1. Determine the volume of 1M NaOH that is required to reach the equivalence point with 25.00 mL of HCl (of unknown concentration). From there, calculate the original concentration of the unknown HCl solution.

Volume of 1M NaOH used = 2.80 mL

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Bunny Greenfelder
Bunny GreenfelderLv2
26 Mar 2019

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Related questions

It took 32.15 mL of 0.0953 M NaOH to reach the equivalence point of a titration when 25.00 mL of unknown concentration of HCl was titrated. Determine the molarity of the HCl solution.

_HCl(aq) + _NaOH ïƒ _NaCl(aq) + _H2O(l)

A student determined their NaOH molarity to be 0.0943 M. This solution was used to standardize 25.00 mL of an HCl solution, requiring 25.73 mL to reach the equivalence point. The HCl solution was then used to determine the weight % of soda ash in 0.5102 g of an unknown sample, requiring 38.77 mL. If the determined NaOH concentration was 5.000% too low (relative error of -5%), how does it change the reported value of weight % soda ash?

Calculate the concentration (in M) of the unknown NaOH solution in the first case.

NaOH volume (mL) HCl volume (mL) [HCl] M
8.00 mL 9.77 mL 0.1599 M

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