culator 1åµomv2 | Online teachin à + ï¹ signment/takeCovalentActivity.do?locator-assignment-take&takeAssignmentsessionl.ocator-assignment-take Use the References to access important values if needed for this question. For the following reaction, 0.249 moles of carbon (graphite) are mixed with 0.305 moles of oxygen gas carbon (graphite) (s) + oxygen(g) â carbon dioxide(g) What is the formula for the limiting reagent? What is the maximum amount of carbon dioxide that can be produced? moles Submit Answer Retry Entire Group more group atteumipts temaining