1
answer
0
watching
84
views
11 Nov 2019
500.0 mL of 0.180 M NaOH is added to 535 mL of 0.200 M weak acid (Ka = 3.37 Ã 10-5), what is the pH of the resulting buffer? HA(a) OH (aq)H2A(aq) pH =
500.0 mL of 0.180 M NaOH is added to 535 mL of 0.200 M weak acid (Ka = 3.37 Ã 10-5), what is the pH of the resulting buffer? HA(a) OH (aq)H2A(aq) pH =
Bunny GreenfelderLv2
7 Apr 2019