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11 Nov 2019
Please write answers clearly
Conversions dealing with area or volume can frequently be derived if you know the linear conversions. For example, if you know that 1 in = 2.54 cm, then it is also true that Therefore: (1 in)^2 = (2.54 cm)^2 1 in^2 = 6.45 cm^2 If we do the same operation to both sides of an equation, the equivalency will be maintained. A cubic container 44.0 cm on a side contains a liquid with a density of 1.13 g/mL. How much does the liquid weigh, in pounds? (1 cm^3 = 1 mL) A block measures 2.05 ft. by 2.71 ft by 25.7 in, and weighs 964.3 lbs. What is the density of the block in grams per cubic centimeter? A square lot is 2.66 acres in area. Calculate the length of one side of the lot, in meters. 1 rod = 5.5 yards: 40 rods = 1 furlong (exact): 8 furlongs = 1 mile = 5280 ft (exact): 1 m = 1.094 yards: 1 acre = 160 rods^2 (exact)
Please write answers clearly
Conversions dealing with area or volume can frequently be derived if you know the linear conversions. For example, if you know that 1 in = 2.54 cm, then it is also true that Therefore: (1 in)^2 = (2.54 cm)^2 1 in^2 = 6.45 cm^2 If we do the same operation to both sides of an equation, the equivalency will be maintained. A cubic container 44.0 cm on a side contains a liquid with a density of 1.13 g/mL. How much does the liquid weigh, in pounds? (1 cm^3 = 1 mL) A block measures 2.05 ft. by 2.71 ft by 25.7 in, and weighs 964.3 lbs. What is the density of the block in grams per cubic centimeter? A square lot is 2.66 acres in area. Calculate the length of one side of the lot, in meters. 1 rod = 5.5 yards: 40 rods = 1 furlong (exact): 8 furlongs = 1 mile = 5280 ft (exact): 1 m = 1.094 yards: 1 acre = 160 rods^2 (exact)
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lonewolff111997Lv10
2 Jan 2022
Keith LeannonLv2
15 Feb 2019
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