A certain reaction has an activation energy of 52.5 kJ/mol. Asthe temperature is increased from 22
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A certain reaction has an activation energy of 54.0 kJ/mol. As the temperature is increased from 22°C to a higher temperature, the rate constant increases by a factor of 7.00. What is the higher temperature?
A certain reaction has an activation energy of 54.0 kJ/mol. As the temperature is increased from 22 degrees Celcius to a higher temperature, the rate constant increases by a factor of 7.00. Calculate the higher temperature.
The rate constant for a reaction is 2.25 * 10 ^ -1 1/s at 22.1 C. If the activation energy is 52.5 kJ/mol, at what temperature would the rate constant equal 1.00 1/s? Is the reaction first or second order?
Please explain your step by step process thoroughly!