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1/ The molar solubility of PbI2 is 1.5 x 10-3 M.

a/ What is the molar concentration of iodide ion in a saturatedPbI2 solution?


b/ Determine the solubility constant, Ksp, for lead(II)iodide


2/ a referring to question 1, qualitatively how is the molarsolubility affected by the addition of lead(II) nitrate to thesolution? explain.

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Irving Heathcote
Irving HeathcoteLv2
7 Jan 2019

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Related questions


The solubility of Lead II iodide (MM(PbI2)=461 g/mole) isdetermined to be 0.545g/L

a) Determine the Kspfor Lead II iodide

b) Determine thesolubility (in mg/L) of Lead II iodide in 0.20M Sodium iodidesolution.

c) 20.0 ml of2.0X10^-4M Lead II Nitrate ( Pb(NO3) solution is added to 50.0 mlof 0.0050M Magnesium Iodide (MgI2). will a precipitate form? Showcalculations.

d) Will the adittionof a strong acid (like HCL) affect the solubility of this salt?explain.

a) Write the dissolution reaction for lead(II) iodide. How many grams of lead(II) iodide will dissolve in 250.0 mL of water? What are the molarities of lead(II) ion and iodide ion? Neglect any volume change due to the lead(II) iodide. Ksp of lead(II) iodide = 1.4 x 10-8

b) How many grams of lead(II) iodide will dissolve in 250.0 mL of 0.35 M HI?

c) Will the solubility of lead(II) iodide in 250.0 mL of 0.35 M HNO3 be the same as (a) or (b) ?

d ) How would the answers to (a) and (c) have compared if the salt under consideration were lead(II) fluoride, rather than lead(II) iodide? Ksp PbF2 = 7.1 x 10-7 KaHF = 7.2 x 10-4

e ) Lead(II) ion forms a 1:1 complex with a particular ligand, L (forms PbL2+) . Write the reaction for formation of the complex ion using รขย€ยœLรขย€ย as the ligand. If the formation constant for this complex is 2.9 x 104 , calculate the solubility of lead(II) iodide in a 1.5 M solution of L.

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