1
answer
0
watching
673
views

Calculate the pH of the solution made by adding 0.50 mol of propanoic acid, (C2H5COOH or HC3H5O2) and 0.30 mol of sodium propanoate (C2H5COONa or NaC3H5CO2) to 1.00 L of water. The value of Ka for C2H5COOH is 1.3 x 10^-5. Please Explain!!

For unlimited access to Homework Help, a Homework+ subscription is required.

Irving Heathcote
Irving HeathcoteLv2
20 Jun 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Start filling in the gaps now
Log in