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28 Sep 2019
Determine the heat capacity of a calorimeter with the givendata
NaOH(aq) + HCl (aq) -> NaCl(aq) + H2O(l) delta H = -57.32kJ
amounts used: 50.0 mL of 2.00 M HCl and 50.0 mL or 2.00 MNaOH
initial temp of both sol. = 16.9 C
max temp during reaction = 30.4 C
density of NaCL = 1.04 g/mL
specific heat of 1.00 M NaCl(aq) = 3.93 J/g-K
answer is 16J/C
Determine the heat capacity of a calorimeter with the givendata
NaOH(aq) + HCl (aq) -> NaCl(aq) + H2O(l) delta H = -57.32kJ
amounts used: 50.0 mL of 2.00 M HCl and 50.0 mL or 2.00 MNaOH
initial temp of both sol. = 16.9 C
max temp during reaction = 30.4 C
density of NaCL = 1.04 g/mL
specific heat of 1.00 M NaCl(aq) = 3.93 J/g-K
answer is 16J/C
NaOH(aq) + HCl (aq) -> NaCl(aq) + H2O(l) delta H = -57.32kJ
amounts used: 50.0 mL of 2.00 M HCl and 50.0 mL or 2.00 MNaOH
initial temp of both sol. = 16.9 C
max temp during reaction = 30.4 C
density of NaCL = 1.04 g/mL
specific heat of 1.00 M NaCl(aq) = 3.93 J/g-K
answer is 16J/C
Keith LeannonLv2
28 Sep 2019
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