Question

The slope of a curve is equal to y divided by 4 more than x^2 at any point (x,y) on the curve.

A) Find a differential equation that represents this:

I got dy/dx=y/(4+x^2)

B) Solve this differential equation:

I got y=sqrt((x^4+8x^2+16)/2x)+C

Here is where I really need help!

C) Suppose its known that as x goes to infinity on the curve, y goes to 1. Find the equation for the curve by using part B and determining the constant. Explain all reasoning.

I am lost about what to do here.