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10 Nov 2019
Please Answer correctly
Given that the acceleration vector is a (t) = (-4 cos(-2t)) i + (-4 sin (-2t)) j + (-4t)k, the initial velocity is v (0) = i + k, and the initial position vector is r (0) = i + j + k, compute: The velocity vector v (t) = i+ j+ k The position vector r (t) = i+ j+ k
Please Answer correctly
Given that the acceleration vector is a (t) = (-4 cos(-2t)) i + (-4 sin (-2t)) j + (-4t)k, the initial velocity is v (0) = i + k, and the initial position vector is r (0) = i + j + k, compute: The velocity vector v (t) = i+ j+ k The position vector r (t) = i+ j+ k
Tod ThielLv2
10 Jan 2019