1
answer
0
watching
84
views
pinksnake690Lv1
6 Nov 2019
Consider the initial value problem dy/dt = cos(yt) with y(-3) = 1 This differential equation is (circle 1): Linear Separable Exact None of these Show transcribed image text
Consider the initial value problem dy/dt = cos(yt) with y(-3) = 1 This differential equation is (circle 1): Linear Separable Exact None of these
Show transcribed image text Reid WolffLv2
1 Aug 2019