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orchidrat80Lv1
6 Nov 2019
please explain.
Explain why the statement is true, or give a specific counter-example: The span of {0} is {0}. It v, w are both vectors in R2 that are non-zero and are not parallel to each other, then Span[ {v, w) ] is all of R2 . It v, w are both vectors in R2 that are non-zero and one is a scalar multiple of the other, then Span[ {v, w} ] is the same as Span[ {v} ] . If v belongs to the span of set of vectors S, then so does cv for every scalar c. Any set of vectors S containing the zero vector 0 must he linearly independent. The zero vector 0 is in the span of any non-empty set of vectors S. If a subset of R4 contains more than 4 vectors, then it must be linearly dependent. There is a subset of p4 that contains more than 4 vectors and is linearly independent. If v Span . then there is a nontrivial solution to the equation Show transcribed image text
please explain.
Explain why the statement is true, or give a specific counter-example: The span of {0} is {0}. It v, w are both vectors in R2 that are non-zero and are not parallel to each other, then Span[ {v, w) ] is all of R2 . It v, w are both vectors in R2 that are non-zero and one is a scalar multiple of the other, then Span[ {v, w} ] is the same as Span[ {v} ] . If v belongs to the span of set of vectors S, then so does cv for every scalar c. Any set of vectors S containing the zero vector 0 must he linearly independent. The zero vector 0 is in the span of any non-empty set of vectors S. If a subset of R4 contains more than 4 vectors, then it must be linearly dependent. There is a subset of p4 that contains more than 4 vectors and is linearly independent. If v Span . then there is a nontrivial solution to the equation
Show transcribed image text