PHYS 1010Q Lecture Notes - Lecture 7: Seat Belt, Stopping Time, Tennis Ball

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18 Sep 2017
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PHYS 1010Q Full Course Notes
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PHYS 1010Q Full Course Notes
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Phys-1010q - lecture 7 - momentum & energy (ch. 6 (pp59-65) & ch 5) When you catch the ball, the impact depends on both the mass of the ball and on its velocity. We thus define the momentum of an object as: Momentum = mass * velocity p = mv. A bowling ball moving at a low speed and a golf ball moving at a high speed can have the same momentum. Uppose the (cid:373)o(cid:373)e(cid:374)tu(cid:373) of a(cid:374) o(cid:271)je(cid:272)t (cid:272)ha(cid:374)ges (cid:271)(cid:455) a(cid:373)ou(cid:374)t p. If the (cid:448)elo(cid:272)it(cid:455) (cid:272)ha(cid:374)ge (cid:448) takes pla(cid:272)e o(cid:448)e(cid:396) a ti(cid:373)e i(cid:374)te(cid:396)(cid:448)al t, the(cid:374) (cid:448) = a* t (cid:449)he(cid:396)e a is the acceleration. Then if we substitute this result into our equation this result into our e(cid:395)uatio(cid:374) fo(cid:396) p, (cid:449)e ha(cid:448)e; P = (cid:373) * (cid:448) = (cid:373) (cid:894)a* t(cid:895) = (cid:373)a t = p. Now newton tells us that the acceleration is due to a net force f = ma.

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