MATH 046 Lecture Notes - Lecture 12: Algebraic Equation, Implicit Function, Integrating Factor

32 views4 pages
15 Dec 2016
Department
Course
Professor

Document Summary

Today we derive the general solutions of the separable equations. y = In the next lecture, we will apply this to solve homogenous equation, which reads y = f ( x y (1) general solutions (2) an example related to linear equation (3) more examples (4) initial value problems. G(y) and separate x and y to two sides of the equality dy dx. G(y)dy = f (x)dx (cid:2) g(y)dy =(cid:2) f (x)dx. After integration, this gives us a algebraic equation between x and y which de nes y as an implicit function of x. In some cases, we can solve y in terms of x explicitly. Let us consider the following equation y + p(x)y = 0. It is easy to see that the equation is both linear and separable. Using method of the integrating factor, we conclude that the general solution is y = e (cid:2) p.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related textbook solutions

Related Documents

Related Questions