PHYS 101 Lecture Notes - Lecture 9: Equations For A Falling Body

23 views2 pages
School
Department
Course
Professor

Document Summary

Neglecting air resistance, all objects fall with the same acceleration. On earth this is about 10 m/s2 (actual value ~9. 8 m/s2. ) For the falling body, the speed of the falling body is directly proportional to the time the object has been falling: (cid:894) peed(cid:895) (cid:894)ti(cid:373)e falli(cid:374)g(cid:895) here the sy(cid:373)(cid:271)ol (cid:862) (cid:862) (cid:373)ea(cid:374)s(cid:862)proportio(cid:374)al to(cid:863) It is easy enough to see that: speed = (10 m/s2)(time (s)) Or speed = (accel)(time) = (a)(t) with a the acceleration of gravity. 80 m 40 m/s time (time) 2 distance distance. 0sec 0 s2 0 m (5 m/s2)(0 s2) 1sec 1 s2 5 m (5 m/s2)(1 s2) 2sec 4 s2 20 m (5 m/s2)(4 s2) 3sec 9 s2 45 m (5 m/s2)(9 s2) 4sec 16 s2 80 m (5 m/s2)(16 s2) For the falling body, the distance traveled by the falling body is directly proportional to the square of the time the object has been falling: (cid:894)dista(cid:374)(cid:272)e(cid:895) (cid:894)ti(cid:373)e falli(cid:374)g(cid:895)(cid:1006)

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents