PH-UY 1013 Lecture Notes - Lecture 1: Net Force, Pythagorean Theorem, Net.

37 views4 pages

limehamster162

7 Sep 2016

School

Department

Course

Professor

For unlimited access to Class Notes, a Class+ subscription is required.

Document Summary

Is the amount that velocity changes by every second. So, an acceleration of 4m/s2 means an object is speeding up by 4m/s each second. b. If an object has a velocity of +100m/s, and accelerates at -10m/s/s, it is slowing down by 10m/s each second. If it maintains that acceleration for longer than 10s, it reverses at t=10s and then speeds up in the negative direction by. If velocity is constant, predict what the graphs would look like. (the position graph is a diagonal line, velocity graph is flat and acceleration is zero. ) f. If acceleration is constant and forward, think . (the position graph will be parabolic, concave up. The velocity graph is a diagonal line and the acceleration graph is flat. : projectiles, keep horizontal (x) and vertical (y) quantities separate!! Make an x-y chart and never mix these quantities in the same equation.

Related Questions

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet.

(a) Find the velocity at time t.

(b) What is the velocity after 1 second?

(d) When is the particle moving in a positive direction?

(e) Find the total distance travelled during the first 6 seconds.

(f) Draw a diagram like a Figure 2 to illustrate the motion of the particle.

(g) Find the acceleration at time t and after 1 second.

(h) Graph the position, velocity, and acceleration functions for 0 ≤ t ≤ 6.

(i) When is the particle speeding up? When is it slowing down?

FIGURE 2

f(t) = t³ – 8t² + 24t

beigewhale140

An object that moves along a straight line has the velocity-versus-time graph shown in the figure below. At time t = 0, the object has position x = 0.

a. At time t = 5 s, is the acceleration of the object positive, negative, or zero?

b. At time t = 8 s, is the object speeding up, slowing down, or moving with constant speed?

c. Write an expression for the position of the object as a function of time.

d. Use your expression from part (c) to determine (if any) at which the object reaches its maximum position.

ultramarineprairie-dog401

1. If an object moves with constant acceleration, its velocity a) must be constant also b) always decrease c) increases by the same amount each second d)change by varying amount depending on its speed.

2. A man leans over the edge of a cliff and throws a rock upward at 4.9 m/s. Neglecting air resistance, two seconds later the rock's speed is a) 9.8 m/s b) 14.7 m/s c) 4.98 m/s d) zero e) none of the above

3. Twelve seconds after starting from rest, an object falling freely will have a speed of a) 10 m/s b) 50 m/s c) more than 100 m/s d)100 m/s.

4. A ball is thrown 125 meters upward and then falls the same distance back to Earth. Neglecting air resistance, its total time in the air is about 10 seconds. about 15 seconds. about 5 seconds. more than 20 seconds.

bluecod895

PH-UY 1013 Lecture Notes - Lecture 1: Net Force, Pythagorean Theorem, Net.

Document Summary

Get access

Related textbook solutions

Physics: Principles with Applications

Related Documents

PH-UY 1013 Lecture Notes - Lecture 1: Dynamic Equilibrium, Statics, Net Force

PH-UY 1013 Lecture 3: Motion in 1D, Constant Acceleration & Free Fall Motion

Physics 1021 Lecture Notes - Lecture 3: Net Force, Contact Force

Related Questions