MATH-3110 Lecture 1: 1.4 vector solutions

A circular cylinder of radius 1 and the hyperbolic paraboloid z = x2 - y2 intersect as shown in Which vector function r(t) = x(t)i + y(t)j + z(t)k has the curve of intersection as its graph if x(0) = 1? r(t) = (cos t)i + (sin t)j + (cos 2t + 1)k r (t) = (cos t)i + (sin t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t + 1)k r(t) = (sin t)i + (cos t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t - 1)k r (t) = (cos t)i + (sin t)j + (cos 2t - 1)k

The graph below is most likely the graph of which of the following equations. r(t) = sin(t)i + cos(t)j + tk, 0 t 4pi r(t) = t cos(t)i + t sin(t)j + tk, 0 t 4pi r(t) = cos(t)i + t sin(t)j + tk, 0 t 4pi r(t) = t cos(t)i + sin(t)j + tk, 0 t 4pi