CHEM 1111 Lecture Notes - Lecture 16: Volumetric Flask, Cuvette, Nitric Acid
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Concentrations of fescn2+ : ((liters of 0. 00200 hscn added) * (initial concentration of hscn)) /1 l= concentration of fescn2+ Solution a: ((0. 001 l hscn) (0. 002 m)) / 1l = 2. 00 *10-6m. Solution b: ((0. 002 l hscn) (0. 002 m)) / 1l = 4. 00 *10-6 m. Solution c: ((0. 003 l hscn) (0. 002 m)) / 1l = 6. 00 *10-6 m. Solution d: ((0. 004 l hscn) (0. 002 m)) / 1l = 8. 00 *10-6 m. Solution e: ((0. 005 l hscn) (0. 002 m)) / 1l = 1. 00 *10-5 m. Solution f: ((0. 006 l hscn) (0. 002 m)) / 1l = 1. 20 *10-5 m. Upon completion, there should be six absorbance readings for equilibrium solutions. Procedure for the demonstration of le chatelier"s principle: prepare a water bath by heating a beaker of water to 70-80 c on a hot plate. Place 1 drop of 1 m fe(no3)3 solution in a clean 18 x 150 mm test tube, and add 1 drop of 1.
