PHY 114 Lecture Notes - Lecture 2: Electric Field, Net Force, Hydrogen Atom

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limeyak740

16 Feb 2018

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The magnitude of the force between two point charges is: Where q1 and q2 are the charges, r is the separation between the two charges. K = 8. 99 x 109 (cid:3015) (cid:3040)(cid:3118)(cid:3004)(cid:3118) . And (cid:2869) (cid:2872) (cid:2976) (cid:2965)(cid:3116) 0 = 8. 85 x 10-12 (cid:3004)(cid:3118)(cid:3015) (cid:3040)(cid:3118) And 0 is called the permittivity of free space. The electric force is directed between the centers of the two point charges. Shows arrows of the two forces pointing from the centers of the objects towards each other. The radius is from the center of the two objects. Shows arrow of the tow force pointing from the centers of the objects away from each other. The radius is still from the center of the two objects. The electric force is an example of a long-range or field force, just like the force of gravity. Compute the force between two people at "arms length" from each other if they each have a 1% excess of electrons.

Related Questions

Coulomb's law for the magnitude of the force F between twoparticles with charges Q and Q' separated by a distance, d is |F| =K *|QQ'|/d2 where K=1/4peo = 8.854*10^-12 nC is the permittivity offree space.

Consider two point charges located on the x axis: one charge, q1 =-19.5nC , is located at x1= -1.680m ; the second charge, q2=31.5nC, is at the origin (x=0.0000).

What is the net force exerted by these two charges on a thirdcharge q3 = 52.5nC placed between q3 and at x3= -1.245m ? Youranswer may be positive or negative, depending on the direction ofthe force.

**Please solve with a numerical answer. I've tried this severaltimes and this is my last attempt on mastering physics.

Coulomb's law for the magnitude of the force between two particleswith charges and separated by a distance is |F| = K |QQ'|/d^2 whereK = 1/4piEo, Eo = 8.854 x 10^-12 C^2/Nxm^2. is the permittivity offree space.

Consider two point charges located on the x axis: one charge, q1 =-11.5nC , is located at x1 = -1.715 m; the second charge, q2 =34.5nC , is at the origin x = 0.00000.

What is the net force exerted by these two charges on a thirdcharge q3 = 49.5nC placed between q1 and q2 at x3 = -1.240m ?

Your answer may be positive or negative, depending on the directionof the force.

find the magnitude of the electric force that the water molecule exerts on the chlorine ion.

The dipole moment of the water molecule (H2O) is 6.17x10^-30 C · m. Consider a water molecule located at the origin whose dipole moment vector p points in the +x-direction. A chlorine ion (Cl−), of charge −1.60 *10^-19 C, is located at x = 1.34 *10^-9 m.

Find the magnitude and direction of the electric force that the water molecule exerts on the chlorine ion.

Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = p/2πε₀y³ can be used, where p is the dipole moment, and y is the distance between ions.

A) What is magnitude______N

B) Direction? +x-direction or -x-direction

C) Is this force attractive or repulsive?

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PHY 114 Lecture Notes - Lecture 2: Electric Field, Net Force, Hydrogen Atom

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