MATH 1520 Lecture Notes - Lecture 1: Tangent

107 views1 pages

Document Summary

The equation of a line can be written in 3 different ways: y = mx + b (slope intercept form, ax + by + c (standard form, y yo = m(x xo) (slope point form) Find the equation of the tangent line to the parabola y=x2 at the point p(1 ,1) Q(x, x2) choose any x point, we chose 1. 5, therefore x2 would be (1. 5)2 which is = to 2. 25. Next find the slope = rise / run = (y2 y1) / (x2 x1) use point q as (x1, y1) and point p as (x2, y2) Now we must find the slope of the tangent, the slope we found was for the parabola not the tangent. To find the slope of the tangent we must use the limit as q approaches p lim = m , therefore lim = x 2 1 = 2.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related textbook solutions

Related Documents

Related Questions