BI308 Lecture 25: BI308 – Lecture #25

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Average fitness of males and females should be equal due to genetic contribution in diploid organisms (sex ratio 1:1) Average reproductive success needs to be the same (fischer) Parents produce equal number of sons and daughters if the sons and daughters cost the same (same size) Say one sex grows more therefore is more costly, therefore parents should produce fewer of those with a higher growth rate so the total investment works out to the be same. Example: if males grow faster and bigger, then they should have less males. Cost per individual (male) cost per individual (female) nmcm = nfcf (number of males)*(cost per male) = (number of females)*(cost per female) What happens if there is differential mortality between the sexes (from conception to independence) If there is a difference, then the parents should produce more of the sex with the higher mortality rate.

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