Computer Science 1033A/B Lecture Notes - Lecture 11: Cd-Rom, Mpeg-4 Part 14, Hard Disk Drive

19 views10 pages
mikekuo58 and 38820 others unlocked
COMPSCI 1033A/B Full Course Notes
25
COMPSCI 1033A/B Full Course Notes
Verified Note
25 documents

Document Summary

Had to copy from one tape to another tape. Had to load up tapes on a machine to copy. Can easily move clips around: no loss of quality. Slight compression occurs in the camcorder when the video is captured. Where will i be puing my video: on the web (bandwidth is an issue, on cd-rom (playback speed is an issue) Who is my audience: will they be on diferent plaforms. 1440 x 1080 pixels 1,555,200 pixels per frame. Audio is 48,000hz and 16 bit = 48,000*1sec*16bits/sample*2=1,536,000bits. 1,555,200 x 24 bits per pixel (for color) = 37,324,800 bits per frame. 37,324,800 * 30 frames per second * 1 second= 1,119,744,000 bits/8 = 139,968,000 bytes =133mb. 133mb + 188kb =~ 133mb lots of storage for just 1 second. Thus a dvd could hold 35 seconds of uncompressed video not a very long movie . Average data rate=ile size/length in seconds of video.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents