Civil and Environmental Engineering 2224 Lecture Notes - Lecture 4: Control Volume
20 Nov 2018
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Start by defining a control volume and labelling inlets and outlets. Since we have one inlet and two outlets, we cannot use the steady flow energy equation for one inlet/one outlet. So let"s solve this right back from first principles. Note: because we"re going back to first principles, we have to calculate the mass flow rates. If we had the simpligfied case of one inlet/one outlet, we would only really have to calculate the mass flow rates if we were looking at something like power. Assuming water at 20oc, so = 998. 2 kg/m3, the corresponding mass flow rates are. With no losses, the equation for conservation of energy becomes. For constant density, and uniform flow conditions at all inlets and outlets, and noting the pump is adding energy to the flow. No turbine, the inlets and outlets are all at the elevation and there are no losses.
