PHL271H1 Lecture : N/A__

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coffeedinosaur756

23 Apr 2011

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Advantages of a grounds based approach: iyre"s discussion: ground. 2 problems with requiring claimants having to stuff their claim into a single: grounds based approach to discrimination, there are many ways in which countries can draft an anti-discrimination law o. Can have a law saying: cannot discrimination, do not say how or anything o. These countries leave it to the courts to decide what is discrimination and what isn"t: what tends to happen is that there is a highly contextualized approach. Will depend on the context of the discrimination. No test: what all features on list have the same is immutability o o. Problem with this: there are things that are immutable. You can"t easily change them at your own will like physical appearance, but isn"t a ground. Arbitra ry in the sense that its an arbitrary feature of them: why its wrong to discriminate based on sex, age , religion www. notesolution. com.

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A radar target is mounted 20 meters above the ground. Thetransmitting antenna is located 500 meters away.

a. Draw a schematic of the situation, showing direct illuminationand the ground bounce.

b. Estimate the antenna height which will cause maximum power to beincident on the target. Hint: You may use the approximation (1+x)^n= 1 + nx if x < 1.

A quantum dot can be thought of as essentially a man-made atom.Consider a 2-dimensional dot (effectively an electron in a squareinfinite well), with a single ground state (with energy Eo = 0.04eV), and a double degenerate first excited state (with energy E1 =0.1eV); the relevant energy levels are shoen below.

ï»¿

1. At T=300K what is the probability that a dot will be excited?

0.02

0.08

0.16

0.4

0.67

2. What is the probability that the dot will be in the groundstate for very high T, i.e., as T approaches infinity?

1/3

1/2

3. For what temperature will about half of the dots be in theirground state, and half in one of the first excited states ?

T = 100K

T = 1000K

There is no temperature at which this canoccur.

4. What is the entropy of a collection of N such dots at verylow temperatures (T-->0) ?

S=0

S=Nk ln(2)

S=Nk ln(3)

http://www.webassign.net/plmechalg/images/4-post-02.GIF

You will solve a general Atwood Machine problem usingconservation of energy techniques. The system starts at rest withheights h1 and h2 as shown in the figure below. It is then releasedand, once in motion, m2 falls to the ground. The string does notstretch.

(a) What is the total initial mechanical energy of the two masses?(Use m1, m2, h1, h2, and g as appropriate.)
Ei = msgh2 +m1gh1

(b) What is the total final mechanical energy of the two masses?(Use m1, m2, h1, h2, vf, and g as appropriate.)
Ef = ?

(c) Use your answers to parts (a) and (b) to eliminate h1. Solvefor vf. (Use m1, m2, h2, and g as appropriate.)
vf = ?

(d) Suppose h2 = 11.6 m, m1 = 9 kg and m2 = 12.5 kg, what is thevelocity at which m2 hits the ground?

PHL271H1 Lecture : N/A__

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