MAT136H1 Lecture 28: Alternating Series
92
MAT136H1 Full Course Notes
Verified Note
92 documents
Document Summary
S = 1 2 n = n. 1 n 1 n n=1 n 1 b n n = 0 lim n . + ( 1 n 1 n + ( 1 n b. S = b1 b 2 + b 3 b 4 l sn l l rn l. S = n=1 n| b n 1 ( 1) n 1 n 4. 0 n| < b n+1 < 1 4. If n=1 a | n| converges, then we say that a n n=1 is absolutely converged is convergent, ( 1) n 1 n=1 convergent n 2 n=1. 1 n 2 is also convergent , therefore n=1 ( 1) n 1 n 2 is absolutely converges, but n=1 a | n| doesn"t converge, then we say that n=1 a n ( 1) n 1 is convergent, but n=1 conditionally convergent. n n=1. If a | n| a n n=1 n=1 is conditionally convergent.
