MATH137 Lecture Notes - Lecture 5: Limit Point, Algebraic Function, Paula Smith
29 views6 pages
20 Mar 2016
School
Department
Course
Professor
![MATH137 Full Course Notes](https://new-docs-thumbs.oneclass.com/doc_thumbnails/list_view/2171654-class-notes-ca-u-of-waterloo-math-137-lecture11.jpg)
36
MATH137 Full Course Notes
Verified Note
36 documents
Document Summary
Let f(x) = 2x3 5x and a = 1; it follows that f( 1) = 2 + 5 = 3. The slope of the straight line joining them, bf af ab. , is the average rate of change: as we replace b with x and let x a, we obtain the instantaneous rate of change, which is just af lim x a xf af ax. Derivative of a function considered as a function: derivative function, notice that in the limit definition af lim. 0 h haf h af the point a could be any value. Thus we can derive a new function, x f lim. - or even df or dxf: the first form, f (x), is shorter; the second, df dx. If a function f is differentiable at a, it is continuous at a. Proof: given f is differentiable at a, we want to show that af xf xf af ax so af lim x a xf ax.
Get access
Grade+
$40 USD/m
Billed monthly
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers