MATH135 Lecture Notes - Lecture 6: Equestrianism, Coprime Integers

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MATH135 Full Course Notes
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MATH135 Full Course Notes
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University of waterloo - fall 2014 - math 135. Find values for x and y such that. With no other requirements, this problem is very easy. So for any value of y that we choose, we can nd a corresponding value of y that will make. For example, if y = 0, the only solution for x is x = 7/9, which is not integer. So there is no solution for x, y z with y = 0. Using the e. e. a. , we can nd values for u and v such that. In fact, u = 1 and v = 2. Now if we multiply the equation above by 7, we obtain. So x = 7 and y = 14 is an integer solution to our original equation. Now, can you nd x and y integers such that. Equations with integers coe cients where only integer solution are being sought are called.

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