ECE106 Lecture 18: ECE 106,University of Waterloo,(p18)

• School: University of Waterloo
• Department: Electrical and Computer Engineering
• Course: ECE106
• Professor: All

Document Summary

Example 3 field to a line of charge. The observe point o lies on the z axes as shown in the figure. The length of the line is l. y dl z. From the symmetry of the line, e is along z direction. The expression in the integration is symmetry to l = 0. Therefore the integration can be simplified to be. To obtain this integration, substitute l z tan , where /2 > 0. Z3(1 + tan2 )3/2 cos2 cos d . Note when < 0, the sign in the last equation will be minus. L2 + 4z 2 (3. 57) (3. 58) (3. 59) (3. 60) (3. 61) (3. 62) (3. 63) (3. 64)