ECE106 Lecture Notes - Lecture 8: Electric Field

• School: University of Waterloo
• Department: Electrical and Computer Engineering
• Course: ECE106
• Professor: All

Document Summary

Figure 3. 4: the total field at some point is the sum of all the field at that point: find e due to each charge at o, add all e vectorially to find the resultant field, i. e. , E tot = e 1 + e 2 + + e n = If a charge q is placed at o, the force acting on q will be f q = qe q . Without doing maths, can you physically think of what is going to happen to the electric field? n=1. If we are very close to the 1c charge, then due to 1/r2 variation, 1 is going to win over and the e should be pointing towards it. 1 r2 (r + d)2 r d (3. 5) So it would look as the two charges are one and they will appear as one +2c charge. The e field should be pointing outwards since the cumulative charge is positive.