CHEM 1050 Lecture Notes - Lecture 14: Equilibrium Constant, Joule, Blood Plasma

27 views3 pages

Document Summary

Because only -t s grows larger with increasing temperature, and g grows less negative for this equation, calculate g at 500 c. Go back to wednesday"s notes and sub in (500 c +273 k = 773 k) for the temperature value free energy and the equilibrium constant remember: g is only for standard values. However, we need to know g for reactions that are not at standard conditions there is a relationship between g and g (at any other conditions) Q < k reaction goes forwards. Q > k reaction goes backwards. Predict the direction in which reaction goes to reach equilibrium. I2 3. 0 x10 -2 mol in a 2. 0 l container take any value you want and make it g . We know that at equilibrium, g = 0 and q = k. Homework: 18. 2, 18. 4, 18. 11, 18. 41, 18. 71, 18. 83, 18. 87, 18. 99. Day 14: free energy and work [oct 10]

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related textbook solutions

Related Documents

Related Questions