PHYS 1041 Lecture Notes - Lecture 6: Boltzmann Constant, Thermal Conductivity, Calorie

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20 Apr 2014
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Then: v= velocity (m/s) v = lf c = speed of light (3. 00 x 108m/s) f=frequency (hz) Blackbody radiation any object that is a perfect absorber of electromagnetic radiation if you know the temperature of blackbody, you can predict its radiation spectrum. The relationship between the temperature (in kelvins) and the peak wavelength of a light wave is: l. 310 mk peak: p= power of light radiation (w, = the stefan boltzmann constant, equal to 5. 67 x 10-5w/(m2k4, a= surface area of absorber (m2, t= temperature in kelvins. If radiator is not perfect, an sign is used to indicate its percentage efficiency in decimals as follows: March 14th the peak wavelength of a light wave increases with temperature higher temperatures mean a shorter wavelength a photon: a packet/bundle of light that behaves as a particle. When: e= energy of a photon (j) Then: h= planck"s constant (6. 63 x 10-34js) f= frequency (hz)

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