math215 Lecture Notes - Lecture 3: Test Statistic, Sp1 Transcription Factor, Analysis Of Variance
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Unit 5 estimation and tests of hypotheses for two or more populations. Solutions to unit 5 self test: a. The formula for the confidence interval for the difference in proportions is (p 1 p 2) z s p 1 p 2 where p 1 1628. To find :z z is such that 98% of the distribution falls to the left of . So, from the normal table, z 2. 05 z. Therefore the 96% confidence interval is (0. 74 0. 60) (2. 05)(0. 0144) 0. 14 0. 0295 or. 0. 11 to 0. 17: let p1 proportion of the male population that exercises regularly, and p2 proportion of the female population that exercises regularly. H0 : p1 p2 0 [p1 is not greater than p2. ] H1 : p1 p2 0 [p1 is greater than p2. ] Select the distribution, as the sample sizes are large and sample sizes multiplied by the sample proportions exceed 5. z. Step 4: test statistic p x1 x2 n1 n2.
