ARTH1002 Lecture 3: Trig Quiz Chapter 4
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Amplitude= absolute value of a period= (2pi)/(pi/4) = 8. Amplitude = (absolute value of) i -2/3 i= 2/3: y= a cos bx where a= amplitude. A= 1/2[3-(-3)]=3 -> since the function completed half the cycle in an interval of [0, 2pi] so the period is 4pi. So the function of the graph is: y= 3 cos 1/2x. Section 4. 2 #22, 54: y= -2 sin (4x-3) y= -2 sin[4(x-3/4)] -> a. Y= a times sin[(x-d)] + c phase shift =d, amplitude= absolute value of a, period= (cid:1006)pi/b. Amplitude- i-2i = 2, period = 2pi/4= pi/2, phase shift = units: amplitude= 3, verticle shift= 3 units downward, period= (2pi)/(1/2) = 4pi. Rest of the questions on the next page. Section 4. 4 # 18, 30: red curve: represents the given function- y=csc(x+pi/3), for one-period interval; Vertical green lines: represents the asymptotes to the curve of the given function;
