ME 2733 Chapter : Ch 6 HW Sol
Document Summary
Assuming that the deformation is entirely elastic, calculate the modulus of elasticity of the aluminum. This problem asks us to compute the elastic modulus of aluminum. 2 , where b0 is the edge length. Combining equations 6. 1, 6. 2, and 6. 5 and solving for the modulus of elasticity, e, leads to. Substitution into this expression, values of l0, b0 l, and f given in the problem statement yields the following. E = (66,700 n)(125 10 3 m) (16. 5 10 3 m)2(0. 43 10 3 m) 71. 2 109 n/m2 71. 2 gpa (10. 4 106 psi) 6. 8 a cylindrical rod of steel (e = 207 gpa, 30 106 psi) having a yield strength of 310 mpa (45,000 psi) is to be subjected to a load of 11,100 n (2500 lbf). If the length of the rod is 500 mm (20. 0 in. ), what must be the diameter to allow an elongation of 0. 38 mm (0. 015 in.
