ECOR 1101 : ECOR 1101 MT2 solution

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pearmole698

7 Jul 2014

School

Carleton University

Department

Engineering Common Core Courses

Course

ECOR 1101

Professor

all

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Document Summary

Q1 locate the y- coordinate of the centroid for the area shown. y da. Formulation y = x y dx * where: da = (8 x) dy. 150 150 (6m) = 4m (6m)(150 n / m) = 450 n. F2 = (6m)(150 n / m) = 900 n. R=f1 +f2 = 450 + 900 = 1350 n (a) R a = f1(4) +f2(3) a = 450(4) + 900(3) (6m) = 3m. Ax + cx = 0 ax = cx = 2250 n . Fy = 0 ay + cy 1350 = 0. Ay(6)+1357(2. 67) = 0 ay = 600 n . Ax + bx = 0 ax = bx = 2250 n . Ay + by 1350 = 0 by = 750 n . Cx bx = 0 cx = 2250 n . Cy by = 0 by = cy = 750 n . Ax = 2250 n ay = 600 n .

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