27 Nov 2021
Problem 61c
Page 474
Section: Problems by Topic
Chapter 11: Liquids, Solids, and Intermolecular Forces
Textbook ExpertVerified Tutor
27 Nov 2021
Given information
The given pairs are as follows:
Step-by-step explanation
Step 1.
are atomic solids.
These two form nonbonding atomic solids which are held together by weak dispersion forces. Hence these solids have very low melting points.
Since its an atomic solid, its melting point is determined by the strength of the intermolecular dispersion forces.
If the dispersion force is stronger more energy is required to break the force between the atoms in the solid and so the solids with stronger force between the atoms will have a higher melting point.
Dispersion force is affected by the size of the atom and molecular weight.
Among ,
is larger in size and has a higher molecular weight.
Thus has a stronger dispersion force than which is smaller in size.
Unlock all Textbook Solutions
Already have an account? Log in