Textbook ExpertVerified Tutor
23 Nov 2021
Given information
The area of the circular metal disk is 
.
The tolerance in the area of the disk is 
.
The value of 
is 
.
Step-by-step explanation
Step 1.
- The tolerance in the area of the disk is .
- Write the inequality by using the fact that tolerance in the area of the disk is and the area of the disk is .
- Consider
as radius and 
as 
. The area is given by 
. Therefore 
. That implies 
. - It can be observed that
. - Substitute for in the equation (1).
- Let the tolerance in the radius as .
- Write the inequality involving the fact that the tolerance of the radius
is . - Substitute the value of in the equation (3).
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7
- Problem 8
- Problem 9
- Problem 10a
- Problem 10b
- Problem 11a
- Problem 11b
- Problem 11c
- Problem 12a
- Problem 12b
- Problem 12c
- Problem 13a
- Problem 13b
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19a
- Problem 19b
- Problem 20a
- Problem 20b
- Problem 21a
- Problem 22
- Problem 23
- Problem 24