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20 Nov 2021
Given information
A chemist is given the task of synthesizing a molecule in two different trials and conducting both processes for the same amount of time. It is needed to describe why a reaction with a lower value of equilibrium constant produces a more desirable product than a reaction with a higher value of the equilibrium constant.
It is given that:
The value of 
is 
.
The value of 
is 
.
The time is 
.
Step-by-step explanation
Step 1.
The equilibrium constant is the relationship between the amount of reactant and product present at equilibrium in a reversible process at a certain temperature.
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Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Solutions
Chapter
Section
- Problem 1a
- Problem 1b
- Problem 1c
- Problem 1d
- Problem 2a
- Problem 2b
- Problem 3
- Problem 4
- Problem 5a
- Problem 5b
- Problem 5c
- Problem 6
- Problem 7a
- Problem 7b
- Problem 7cc
- Problem 8a
- Problem 8b
- Problem 8c
- Problem 9
- Problem 10
- Problem 11a
- Problem 11b
- Problem 11c
- Problem 12a
- Problem 12b
- Problem 12c
- Problem 13a
- Problem 13b
- Problem 13c
- Problem 13d
- Problem 14
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31a
- Problem 31b
- Problem 31c
- Problem 32a
- Problem 32b
- Problem 32c
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41a
- Problem 41b
- Problem 41c
- Problem 42a
- Problem 42b
- Problem 42c
- Problem 43a
- Problem 43b
- Problem 43c
- Problem 44a
- Problem 44b
- Problem 44c
- Problem 45a
- Problem 45b
- Problem 45c
- Problem 45d
- Problem 46a
- Problem 46b
- Problem 46c
- Problem 46d
- Problem 47a
- Problem 47b
- Problem 47c
- Problem 48a
- Problem 48b
- Problem 48c
- Problem 49
- Problem 50
- Problem 51a
- Problem 51b
- Problem 51c
- Problem 51d
- Problem 51e
- Problem 51f
- Problem 52a
- Problem 52b
- Problem 52c
- Problem 52d
- Problem 52e
- Problem 52f