Problem 25

Given information

A tabular representation showing the concentration of versus time for the reaction

is given. 

Step-by-step explanation

To find the order of the reaction from this tabular data two methods can be used, either graphical method or either simple mathematical tricky method. For simplicity here mathematical method is used instead of the graphical method.

S.NO.	Time ()	Concentration  ( Given )	initial concentration - next successive concentration	ln ( )	ln(  ) - Next successive ln()	1/(AB)	1/() - next successive 1/()
1	o	0.950	0.950-0.459  =0.491	-0.051	0.051-0.778 =0.727	1.052	1.052-2.178=1.126
2	50	0.459	0.459-0.302  =0.157	-0.778	0.778-1.197 =0.419	2.178	2.178-0.835= 1.343
3	100	0.302	0.302-0.225 =0.077	-1.197	1.197-1.491 =0.294	0.835	0.835-0.670=0.165
4	150	0.225	0.225-0.180 =0.045	-1.491	1.491-1.714 =0.223	0.670	0.670-0.583=0.087
5	200	0.180	0.180-0.149 =0.031	-1.714	1.714-1.903 =0.189	0.583	0.583-0.525=0.058
6	250	0.149	0.149-0.128 =0.021	-1.903	1.903-2.055 =0.152	0.525	0.525-0.486=0.039
7	300	0.128	0.128-0.112 =0.016	-2.055	2.055-2.189 =0.134	0.486	0.486-0.456=0.03
8	350	0.112	0.112-0.0994 =0.0126	-2.189	2.189-2.308 =0.119	0.456	0.456-0.433=0.023
9	400	0.0994	0.0994-0.0894 =0.01	-2.308	2.308-2.414 =0.106	0.433	0.433-0.414=0.019

So from the above table, the calculated values of [1/() - next successive value of  1/) ) shows that the values are almost near to each other and will provide a graph of a straight line, hence the reaction is of second-order reaction.