Textbook ExpertVerified Tutor
9 Nov 2021
Given information
Note that the given expression is 
, and 
.
Step-by-step explanation
Step 1.
Take .
Know that 
is the point of inflection.
Substitute the values in the equation.
Therefore, the interval will be 
.
Hence,
Concave downward in the interval of 
.
.Concave upward in the interval of 
.
.These points are points of inflection
.
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
Solutions
Chapter
Section
- Problem 1
- Problem 2
- Problem 3
- Problem 4
- Problem 5
- Problem 6
- Problem 7a
- Problem 7b
- Problem 7c
- Problem 7e
- Problem 8a
- Problem 8b
- Problem 8c
- Problem 8d
- Problem 8e
- Problem 9a
- Problem 9b
- Problem 9c
- Problem 9d
- Problem 9e
- Problem 10a
- Problem 10b
- Problem 10c
- Problem 10d
- Problem 10e
- Problem 11a
- Problem 11b
- Problem 11c
- Problem 11d
- Problem 12a
- Problem 12b
- Problem 12c
- Problem 12d
- Problem 12e
- Problem 13a
- Problem 13b
- Problem 13c
- Problem 13d
- Problem 13e
- Problem 14a
- Problem 14b
- Problem 14c
- Problem 14d
- Problem 14e
- Problem 15
- Problem 16
- Problem 17
- Problem 18
- Problem 19
- Problem 20a
- Problem 20b
- Problem 20c
- Problem 20d
- Problem 20e
- Problem 21
- Problem 22
- Problem 23
- Problem 24
- Problem 25
- Problem 26a
- Problem 26b
- Problem 27
- Problem 28
- Problem 29
- Problem 30
- Problem 31
- Problem 32
- Problem 33
- Problem 34
- Problem 35
- Problem 36
- Problem 37
- Problem 38
- Problem 39
- Problem 40
- Problem 41
- Problem 42
- Problem 43
- Problem 44
- Problem 45
- Problem 46
- Problem 47
- Problem 48a
- Problem 48b
- Problem 48c
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57
- Problem 58
- Problem 59a
- Problem 59b
- Problem 59c
- Problem 60
- Problem 61
- Problem 62
- Problem 63a
- Problem 63b
- Problem 63c
- Problem 64a
- Problem 64b
- Problem 64c
- Problem 65a
- Problem 65b